Showing posts with label Chemistry. Show all posts
Showing posts with label Chemistry. Show all posts

Friday, June 28, 2024

Atomic Structure

Atoms are the building blocks of elements. They are the smallest parts of an element that chemically react. The first atomic theory, proposed by John Dalton in 1808, regarded atom as the ultimate indivisible particle of matter. Towards the end of the nineteenth century, it was proved experimentally that atoms are divisible and consist of three fundamental particles: electrons, protons and neutrons. The discovery of sub-atomic particles led to the proposal of various atomic models to explain the structure of atom.
Thomson in 1898 proposed that an atom consists of uniform sphere of positive electricity with electrons embedded into it. This model in which mass of the atom is considered to be evenly spread over the atom was proved wrong by Rutherford’s famous alpha-particle scattering experiment in 1909. Rutherford concluded that atom is made of a tiny positively charged nucleus, at its centre with electrons revolving around it in circular orbits. Rutherford model, which resembles the solar system, was no doubt an improvement over Thomson model but it could not account for the stability of the atom i.e., why the electron does not fall into the nucleus. Further, it was also silent about the electronic structure of atoms i.e., about the distribution and relative energies of electrons around the nucleus. The difficulties of the Rutherford model were overcome by Niels Bohr in 1913 in his model of the hydrogen atom. Bohr postulated that electron moves around the nucleus in circular orbits. Only certain orbits can exist and each orbit corresponds to a specific energy. Bohr calculated the energy of electron in various orbits and for each orbit predicted the distance between the electron and nucleus. Bohr model, though offering a satisfactory model for explaining the spectra of the hydrogen atom, could not explain the spectra of multi-electron atoms. The reason for this was soon discovered. In Bohr model, an electron is regarded as a charged particle moving in a well defined circular orbit about the nucleus. The wave character of the electron is ignored in Bohr’s theory. An orbit is a clearly defined path and this path can completely be defined only if both the exact position and the exact velocity of the electron at the same time are known. This is not possible according to the Heisenberg uncertainty principle. Bohr model of the hydrogen atom, therefore, not only ignores the dual behaviour of electron but also contradicts Heisenberg uncertainty principle. 
Erwin Schrödinger, in 1926, proposed an equation called Schrödinger equation to describe the electron distributions in space and the allowed energy levels in atoms. This equation incorporates de Broglie’s concept of wave-particle duality and is consistent with Heisenberg uncertainty principle. When Schrödinger equation is solved for the electron in a hydrogen atom, the solution gives the possible energy states the electron can occupy [and the corresponding wave function(s) (ψ) (which in fact are the mathematical functions) of the electron associated with each energy state]. These quantized energy states and corresponding wave functions which are characterized by a set of three quantum numbers (principal quantum number n, azimuthal quantum number l and magnetic quantum number ml) arise as a natural consequence in the solution of the Schrödinger equation. The restrictions on the values of these three quantum numbers also come naturally from this solution. The quantum mechanical model of the hydrogen atom successfully predicts all aspects of the hydrogen atom spectrum including some phenomena that could not be explained by the Bohr model.
According to the quantum mechanical model of the atom, the electron distribution of an atom containing a number of electrons is divided into shells. The shells, in turn, are thought to consist of one or more subshells and subshells are assumed to be composed of one or more orbitals, which the electrons occupy. While for hydrogen and hydrogen like systems (such as He+, Li2+ etc.) all the orbitals within a given shell have same energy, the energy of the orbitals in a multi-electron atom depends upon the values of n and l: The lower the value of (n + l ) for an orbital, the lower is its energy. If two orbitals have the same (n + l ) value, the orbital with lower value of n has the lower energy. In an atom many such orbitals are possible and electrons are filled in those orbitals in order of increasing energy in accordance with Pauli exclusion principle (no two electrons in an atom can have the same set of four quantum numbers) and Hund’s rule of maximum multiplicity (pairing of electrons in the orbitals belonging to the same subshell does not take place until each orbital belonging to that subshell has got one electron each, i.e., is singly occupied). This forms the basis of the electronic structure of atoms.

Wednesday, December 29, 2021

Some Basic Concepts of Chemistry

  1. Some Basic Concepts of Chemistry

The study of chemistry is very important as its domain encompasses every sphere of life. Chemists study the properties and structure of substances and the changes undergone by them. All substances contain matter, which can exist in three states – solid, liquid or gas. The constituent particles are held in different ways in these states of matter and they exhibit their characteristic properties. 


Classification of Matter


Matter can also be classified into elements, compounds or mixtures. An element contains particles of only one type, which may be atoms or molecules. The compounds are formed where atoms of two or more elements combine in a fixed ratio to each other. Mixtures occur widely and many of the substances present around us are mixtures.

When the properties of a substance are studied, measurement is inherent. 


Measurements of Substances in SI System


The quantification of properties requires a system of measurement and units in which the quantities are to be expressed. Many systems of measurement exist, of which the English and the Metric Systems are widely used. The scientific community, however, has agreed to have a uniform and common system throughout the world, which is abbreviated as SI units (International System of Units).

Since measurements involve recording of data, which are always associated with a certain amount of uncertainty, the proper handling of data obtained by measuring the quantities is very important. The measurements of quantities in chemistry are spread over a wide range of 10-31 to 1023. Hence, a convenient system of expressing the numbers in scientific notation is used. The uncertainty is taken care of by specifying the number of significant figures, in which the observations are reported. The dimensional analysis helps to express the measured quantities in different systems of units. Hence, it is possible to interconvert the results from one system of units to another.


Basic Laws of Chemical Combination


The combination of different atoms is governed by basic laws of chemical combination — these being the 

1. Law of Conservation of Mass, 2. Law of Definite Proportions, 3. Law of Multiple Proportions, 

4. Gay Lussac’s Law of Gaseous Volumes and 5. Avogadro Law. 

All these laws led to the Dalton’s atomic theory, which states that atoms are building blocks of matter. 


Atomic and Molecular Mass


The atomic mass of an element is expressed relative to 12C isotope of carbon, which has an exact value of 12u. Usually, the atomic mass used for an element is the average atomic mass obtained by taking into account the natural abundance of different isotopes of that element. The molecular mass of a molecule is obtained by taking sum of the atomic masses of different atoms present in a molecule. The molecular formula can be calculated by determining the mass per cent of different elements present in a compound and its molecular mass.


Avogadro Number

 

The number of atoms, molecules or any other particles present in a given system are expressed in the terms of Avogadro constant (6.022 × 1023). This is known as 1 mol of the respective particles or entities.


Stoichiometric Calculations


Chemical reactions represent the chemical changes undergone by different elements and compounds. A balanced chemical equation provides a lot of information. The coefficients indicate the molar ratios and the respective number of particles taking part in a particular reaction. The quantitative study of the reactants required or the products formed is called stoichiometry. Using stoichiometric calculations, the amount of one or more reactant(s) required to produce a particular amount of product can be determined


The Amount of Substance in a Solution


The amount of substance present in a given volume of a solution is expressed in number of ways, e.g., 1. Mass Per cent, 2. Mole fraction, 3. Molarity and 4. Molality.

Saturday, May 23, 2020

2. Acids, Bases, and Salts Class X

Learning Points:
1. Acids, Bases, and Salts.
2. Chemical properties acids and base.
3. How to acids and Bases react with metal.
4. Acids and Bases react with each other.
5. Reaction metallic Oxides with acids.
6. Reaction of non metallic Oxides with base.
7. What do all acids and all bases have in common.
8. What happens to an Acids or a Base in water solution.
9. How strong are acid or base solution.
10. Importance of pH in everyday life.
11. Family of salts
12. pH of salts
13. Chemicals from common salts

Questions - Answers
NCERT Textbook
Page No. 2.
Question:
You have been provided with three test tubes. One of them contains distilled water and the other two contain an acidic solution and a basic solution, respectively. If you are given only red litmus paper, how will you identify the contents of each test tube?
Answer
We dip the litmus paper one by one in each test tubes.
If there is no change in the colour of litmus paper we say that solutions can be either distilled water or acidic.
Now, we dip the litmus paper in the third test tube in which colour is changed and we clear that this is basic solution. Now, the colour of litmus paper becomes blue.
Now, we dip the litmus paper in other two test tubes. If colour is changed we say it is acidic otherwise distilled water.
In this process we identify the solutions of test tubes.

Page No.6.
Questions
1. Why should curd or sour substances not be kept in brass and copper vessel?
Answer:
The curd or sour substances are acidic. Copper and brass are matal and alloy of metal. When curd or sour substances reacts with metal displace hydrogen gas and form salt together with harmful products.
Acid + metal    -> hydrogen + salt .
2HSO₄ + 2Cu -> 2CuSO₄ + H₂
Therefore, curd or sour subtances shoud not kept in brass and brass or copper vessel.

Q.No.2. Which gas is usually librated when an acid reacts with a metal? Illustrate with an example. How will you test for presence of this gas?
Answer :
Hydrogen gas is librated during the chemical reaction between acids and salts.

Example is given below

Zn + 2H₂SO₄ -> Zn(SO₄) + 2H₂.
We can test the evolved hydrogen gas by its burning with a pop sound when candle is brought near the gas.

Q.No.3. Metal compound A reacts with dilute hydrochloric acid to produce effervescence. The gas evolved extinguishes a burning candle. Write a balanced chemical equation for the reaction if one of the compound formed is calciumchloride.

Answer:

The balanced chemical equation is given below.
CaCO₃ + 2HCl -> CaCl₂ + CO₂ + H₂O

Monday, April 20, 2020

1. रासायनिक अभिक्रियाएँ एवं समीकरण

कक्षा दशम्
अध्याय 1
रासायनिक अभिक्रियाएँ एवं समीकरण
प्रश्नोत्तर NCERT Textbook
1.1 रासायनिक समीकरण
प्रश्न1. वायु मे जलाने से पहले मैग्नीशियम रिबन को साफ क्यों किया जाता है?
उतरः
मैग्नीशियम एक अति क्रियाशील धातू है अतः यह हवा के साथ प्रतिक्रिया करके मैग्नीशियम ऑक्साइड  का एक परत बनाता है जो आगे कि प्रतिक्रिया को जारी रखने में बाधा पहुँचाता है। इसलिए, वायु अथवा ऑक्सीजन में जलाने से पहले मैग्नीशियम रिबन को रेगमाल(Sand Paper) से रगडकर साफ कर लिया जाता है।

प्रश्न2. निम्नलिखित रासायनिक अभिक्रियाओॆ के लिए संतुलित समीकरण लिखिएः
(i) हाइड्रोजन + क्लोरीन → हाइड्रोजन क्लोराइड
उतरः
H₂ + Cl₂ → 2HCl
(ii) बेरियम क्लोराइड + ऐलुमीनियम सल्फेट → बेरियम सल्फेट + ऐलुमिनियम क्लोराइड
उतरः
(iii) सोडियम + जल → सोडियम हाइड्रोक्साइड + हाड्रोजन
उतरः
2Na + 2H₂O → 2NaOH + H₂
प्रश्न 3. निम्नलिखित अभिक्रियाओं के लिए उनकी अवस्था के संकेतो के साथ संतुलित रासायनिक समीकरण लिखिएः
(i) जल में बेरियम क्लोराइड तथा सोडियम सल्फेट के विलयन अभिक्रिया करके सोडियम क्लोराइड का विलयन तथा अघुलनशील बेरियम सल्फेट का अवक्षेप बनाते हैं।
उतरः
BaCl₂(aq) + Na₂SO₄(s) → BaSO₄(s) + 2NaCl(aq)
(ii) सोडियम हाइड्रोक्साइड का विलयन (जल में) हाइड्रोक्लोरिक अम्ल के विलयन (जल में) से अभिक्रिया करके सोडियम क्लोराइड का विलयन तथा जल बनाते है।
उतरः
NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

1.2 रासायनिक अभिक्रियाओं के प्रकार
प्रश्न1. किसी पदार्थ X के विलयन का उपयोग सफेदी करने के लिए होता है।
(i) पदार्थ X का नाम तथा इसको सूत्र लिखिए।
उतरः
 कैल्सियम ऑक्साइड अथवा बिना बुझा हुआ चूना
रासायनिक सूत्रः (CaO)
(ii) ऊपर (i) में लिखे पदर्थ X की जल के साथ अभिक्रिया लिखिए।
उतरः
CaO एवं H₂O की रासायनिक अभिक्रिया नीचे दिया गया है।
CaO + H₂O → Ca(OH)₂(aq) + ऊष्मा
प्रश्न 2. क्रियाकलाप 1.7 में एक परखनली में एकत्रित गैस की मात्रा दूसरी से दोगुनी क्यो? उस गैस का नाम बताइए।
उतरः
वियोजन अभिक्रिया के कारण परखनली में एकत्रित गैस हाइड्रोजन का आयतन ऑक्सीजन से से दोगुनी है।

1.2.3 विस्थापन अभिक्रिया
प्रश्न1. जब लोहे की कील को कॉपर सल्फेट के विलयन में डुबोया जाता है तो विलयन का रंग क्यो बदल जाता है?
उतरः
इस अभिक्रिया में, लोहे ने कॉपर को कॉपर सल्फेट के विलयन से विस्थापित कर दिया। इस कारण विलयन के रंग के साथ-साथ लोहे के कील का भी रंग बदल जाता है।
इस अभिक्रिया को विस्थापन अभिक्रिया कहा जाता है।
ऱासायनिक अभिक्रिया को नीचे दिखाया गया है।
Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)

प्रश्न 2. क्रियाकलाप 1.10 से भिन्न द्विविस्थापन अभिक्रिया का एक उदाहरण दीजिए।
उतरः
द्विविस्थापन अभिक्रिया का उदाहरण नीचे दिया गया है।
Na₂SO₄(aq) + BaCl₂ → BaSO₄(s) + 2NaCl(aq)
प्रश्न 3. निम्न अभिक्रियाओं में उपचयित पदार्थ की पहचान कीजिएः
(i) 4Na(s) + O₂ → 2Na₂O(s)
उतरः
इस अभिक्रिया में सोडियम उपचयित पदार्थ है।
(ii) CuO(s) + H₂(g) → Cu(s) + H₂O(l)
उतरः
इस अभिक्रिया में हाइड्रोजन उपचयित पदार्थ है।

अभ्यास
प्रश्न 1. नीचे दी गयी अभिक्रिया के संबंध मे कौन सा कथन सत्य है?
2PbO(s) + C(s) → 2Pb(s) + CO₂(g)
(a) सीसा अपचयित हो रहा है।
(b) कार्बन डाइऑक्साइड उपचयित हो रहा है।
(c) कार्बन उपचयित हो रहा है।
(d) लेड ऑक्साइड अपचयित हो रहा है।
(i) (a) एवं (b)
(ii) (a) एवं (c)
(iii) (a), (b) एवं (c)
(iv) सभी
उतरः
सीसा अपचयित हो रहा है एवं कार्बन डाइऑक्साइड उपचयित हो रहा है।
अतः सही विकल्प (ii) होगा।

प्रश्न2. Fe₂O₃ + 2Al →Al₂O₃ + 2Fe
उपर दी गयी अभिक्रिया किस प्रकार की हैः
(a) संयोजन अभिक्रिया
(b) द्विविस्थापन अभिक्रिया
(c) वियोजन अभिक्रिया
(d) विस्थापन अभिक्रिया
उतरः
यह एक प्रकार का विस्थापन अभिक्रिया है क्योंकि अल्युमिनियम, लोहे को उनके योगिक से विस्थापित कर रहा है।
अतः सही विकल्प (d) होगा।

प्रश्न 3. लौह चूर्ण पर तनु हाइड्रोक्लोरिक अम्ल डालने से क्या होता है? सही उत्तर पर निशान लगाइए।
(a) हाइड्रोजन गैस एवं आयरन क्लोराइड बनता है।
(b) क्लोरीन गैस एवं आयरन हाइड्रॉक्साइड बनता है।
(c) कोई अभिक्रिया नही होती है।
(d) आयरन लवण एवं जल बनता है।
उत्तरः
हाइड्रोजन गैस एवं आयरन क्लोराइड बनता है।
 

1.Chemical Reactions and Equations

Class X
Chapter 1.
Chemical Reactions and Equations
Questions Answers (NCERT Textbook)

1.1 Chemical Equations

Q.No.1. Why should a magnesium ribbon be cleaned before burning in air ?
Answer:
Magnesium ribbon is very reactive metal so it easily reacts with air and make a layer of magnesium oxide. The layer of magnesium oxide is quite stable and prevents further reaction of magnesium with air or oxygen. Therefore, magnesium ribbon is cleaned by sand paper to remove the layer of magnesium oxide before burning in air. Magnesium ribbon burns with air and gives magnesium oxide.
The word equation for the reaction would be
Magnesium + Oxygen → Magnesium Oxide.
This word equation may be represented by following chemical equation.
2Mg + O₂ → 2MgO

Q.No.2. Write the balanced equation for the following chemical reactions.
(i) Hydrogen + Chlorine → Hydrogen chloride
Answer:
The above word equation may be represented by following chemical equation
H₂ + Cl₂ → 2HCl

(ii) Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride
Answer:
The above word equation may be represented by
3BaCl₂ + Al₂(SO₄)₃ → 3BaSO₄ + 2AlCl₃

(iii) Sodium + Water → Sodium hydroxide + Oxygen
Answer:
The above word equation may be represented by following chemical equation.
2Na + 2H₂O → 2NaOH + H₂

Q.No.3. Write a balanced chemical equation with symbols for the following reactions.
(i) Solution of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride.
Answer:
The above equation may be represented by following chemical equation.
BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)

(ii) Sodium hydroxide solution (in water) reacts with hydrochloric acid solution (in water) to produce sodium chloride solution and water.
Answer:
The above equation may be represented by following chemical equation.
NaOH(aq) + HCl(aq) → NaCl(l) + H₂O(l)

Monday, October 7, 2019

11. Alcohols, Phenols and Ethers

Alcohols, Phenols and Ethers

Class XII
Subject : Chemistry

Alcohols

Alcohols are compounds in which a hydroxyl(-OH) group attached to the saturated carbon atom.
General formula of alcohol - R-OH
The hydroxyl group is the functional group of alcohols.

Alcohols containing one hydroxyl are called Monohydric Alcohols.
Alcohols with two, three, or more hydroxyl groups are known as Dihydric Alcohols, Trihydric Alcohols, and Polyhydric Alcohols respectively.
For example,


Primary, Secondary and Tertiary Alcohols

Monohydric alcohols are classified as primary, secondary or tertiary depending upon whether the -OH group is attached to primary, secondary or a tertiary carbon.


Structure

Consider about the structure of Methyl Alcohol (CH₃OH). In methyl alcohol both oxygen and carbon are sp³ hybridized. Two of the sp³ orbitals of oxygen are completely filled and cannot take part in bond formation.

The C-O bond methyl alcohol is formed by overlap of an sp³ orbital of carbon and an sp³ orbital of oxygen. The O-H bond is formed by overlap of an sp³ orbital of oxygen and s orbital of hydrogen. The C-O-H bond angle is 105⁰. It is less than the normal tetrahedral angle. This is because the two completely filled sp³ orbitals of oxygen repel each other. This result in reduction of the bond angle.

Structure of Methyl Alcohol is given below



















Continue ................ 

Friday, October 4, 2019

3. Atoms and Molecules IX Chapter 3

Page 32

Q.No. 1:

In a reaction 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g
of carbon dioxide, 0.9g water and 8.2 g of sodium ethanoate. Show that these observations are in
agreement with the law of conservation of mass.
Sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water

Answer:

In a reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate,
carbondioxide, and water.
 Sodium + Ethanoic → Sodium + Carbon + Water
Carbonate acid ethanoate dioxide

Mass of sodium carbonate = 5.3g (Given)
Mass of ethanoic acid = 6g (Given)
Mass of sodium ethanoate = 8.2g (Given)
Mass of carbon dioxide = 2.2 (Given)
Mass of water = 0.9g (Given)
Now, total mass before the reaction = (5.3 + 6)g
= 11. 3g
and total mass after the reaction = (8.2 + 2.2 + 0.9)g
= 11.3g
Therefore, Total mass before the reaction = Total mass after the reaction
Hence, the given observations are in agreement with the law of conservation of ma

Page 33
Q.No. 2:

Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen
gas would be required to react completely with 3g of hydrogen gas?

Answer:

It is given that the ratio of hydrogen and oxygen by mass to form water is 1:8. Then, the mass of
oxygen gas required to react completely with 1g of hydrogen gas is 8g. Therefore, the mass of
oxygen gas required to react completely with 3g of hydrogen gas is 8 × 3g = 24 g.

Q.No. 3:

Which postulate of Dalton's atomic theory is the result of the law of conservation of mass?

Answer:

The postulate of Dalton's atomic theory which is a result of the law of conservation of mass is
“Atoms are indivisible particles, which can neither be created nor destroyed in a chemical
reaction”.

Q.No. 4:

Which postulate of Dalton's atomic theory can explain the law of definite proportions?

Answer:

The postulate of Dalton's atomic theory which can explain the law of definite proportion is “The
relative number and kind of atoms in a given compound remains constant”.

Page 35
Q.No. 1:

Define atomic mass unit.

Answer:

Mass unit equal to exactly one- twelfth the mass of one atom of carbon - 12 is called one atomic
mass unit. It is written as 'u'.

Q.No. 2:

Why is it not possible to see an atom with naked eyes?

Answer:

The size of an atom is so small that it is not possible to see it with naked eyes. Also, atom of an
element does not exist independently.

Page 39

Q.No. 1:

Write down the formula of
(i) sodium oxide
(ii) aluminium chloride
(iii) sodium suphide
(iv) magnesium hydroxide

Answer:

(i) Sodium oxide → Na2O
(ii) Aluminium chloride → AlCl3
(iii) Sodium suphide → Na2S
(iv) Magnesium hydroxide → Mg(OH)2

Q.No. 2:

Write down the names of compounds represented by the following formula:
(i) Al2(SO4)3
(ii) CaCl2
(iii) K2SO4
(iv) KNO3
(v) CaCO3

Answer:

(i) Al(SO4)3→ Aluminium sulphate
(ii) CaCl2→ Calcium chloride
(iii) K2SO4→ Potassium sulphate
(iv) CaCO3→ Calcium carbonate

Q.No. 3:

What is meant by the term chemical formula?

Answer:

The chemical formula of a compound means the symbolic representation of the composition of a
compound. From the chemical formula of a compound, we can know the number and kinds of
atoms of different elements that constitute the compound. For example, from the
chemical formula CO2 of carbon dioxide, we come to know that one carbon atom and two oxygen
atoms are chemically bonded together to form one molecule of the compound, carbon dioxide.

Question 4:

How many atoms are present in a
(i) H2S molecule and
(ii) PO4
3-
ion?

Answer :

(i) In an H2S molecule, three atoms are present; two of hydrogen and one of sulphur.
(ii) In a PO4
3-
ion, five atoms are present; one of phosphorus and four of oxygen.

Page 40

Question 1:

Calculate the molecular masses of H2, O2, Cl2, CO2, CH4, C2H6, C2H4, NH3, CH3OH.

Answer:

Molecular mass of H2 = 2 × Atomic mass of H
= 2 × 1 = 2u
Molecular mass of O2 = 2 × Atomic mass of O
= 2 × 16 = 32u
Molecular mass of Cl2 = 2 × Atomic mass of Cl
= 2 × 35.5 = 71 u
Molecular mass of CO2 = Atomic mass of C + 2 × Atomic mass of O
= 12 + 2 × 16 = 44 u
Molecular mass of CH4 = Atomic mass of C + 4 × Atomic mass of H
= 12 + 4 × 1 = 16 u
Molecular mass of C2H6 = 2 × Atomic mass of C + 6 × Atomic mass of H
= 2 × 12 + 6 × 1 = 30u
Molecular mass of C2H4 = 2 × Atomic mass of C + 4 × Atomic mass of H
= 2 × 12 + 4 × 1 = 28u
Molecular mass of NH3 = Atomic mass of N + 3 × Atomic mass of H
= 14 + 3 × 1 =17 u
Molecular mass of CH3OH Atomic mass of C+4 ×Atomic mass of H+Atomic mass of O
= 12 + 4 × 1 + 16 = 32 u

Q.No. 2:

Calculate the formula unit masses of ZnO, Na2O, K2CO3, given masses of Zn = 65u, Na = 23u, K
= 39u, C = 12u, and O = 16u.

Answer :
Formula unit mass of ZnO = Atomic mass of Zn + Atomic mass of O
= 65 + 16 = 81 u
Formula unit mass of Na2O = 2 × Atomic mass of Na + Atomic mass of O
= 2 × 23 + 16 = 62u
Formula unit mass of K2CO3
= 2 × Atomic mass of K + Atomic mass of C + 3 × Atomic mass of O
= 2 × 39 + 12 + 3 × 16 = 138u

Page 42

Question 1:
If one mole of carbon atoms weighs 12 gram, what is the mass (in gram) of 1 atom of carbon?

Answer:

One mole of carbon atoms weighs 12g (Given)
i.e., mass of 1 mole of carbon atoms = 12g
Then, mass of 6.022× 1023 number of carbon atoms = 12g
Therefore, mass of 1 atom of carbon =
12
6.022× 10– 23 g g
= 1.9926 × 10– 23 g

Q.No. 2:

Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass
of Na = 23u, Fe =56 u)?

Answer 2:

Atomic mass of Na = 23u (Given)
Then, gram atomic mass of Na = 23g
Now, 23g of Na contains = 6.022×1023 number of atoms
Thus, 100g of Na contains =
6.022×1023 ×10⁻²³
number of atoms
= 2.6182 × 1024 number of atoms
Again, atomic mass of Fe = 56u (Given)
Then, gram atomic mass of Fe = 56g
Now, 56 g of Fe contains = 6.022×1023 number of atoms
Thus, 100 g of Fe 6.022×1023 ×100
56
number of atoms
= 1.0753 × 1024 number of atoms
Therefore, 100 grams of sodium contain more number of atoms than 100 grams of iron.

Q.No. 5:

Give the names of the elements present in the following compounds:
(a) Quick lime
(b) Hydrogen bromide
(c) Baking powder
(d) Potassium sulphate.

Answer:

Compound Chemical formula Elements present
Quick lime CaO Calcium, oxygen
Hydrogen bromide HBr Hydrogen, bromine
Baking powder NaHCO3 Sodium, hydrogen, carbon,
oxygen
Potassium sulphate K2SO4 Potassium, sulphur, oxygen

Q.No. 6:

Calculate the molar mass of the following substances:
(a) Ethyne, C2H2
(b) Sulphur molecule, S8
(c) Phosphorus molecule, P4 (atomic mass of phosphorus = 31)
(d) Hydrochloric acid, HCl
(e) Nitric acid, HNO3

Answer:

(a) Molar mass of ethyne, C2H2 = 2 × 12 + 2 × 1 = 28g
(b) Molar mass of sulphur molecule, S8 = 8 × 32 = 256g
(c) Molar mass of phosphorus molecule, P4 = 4 × 31 = 124g
(d) Molar mass of hydrochloric acid, HCl = 1 + 35.5 = 36.5g
(e) Molar mass of nitric acid, HNO3 = 1 + 14 + 3 × 16 = 63g

Q.No. 7:

What is the mass of
(a) 1 mole of nitrogen atoms?
(b) 4 mole of aluminium atoms (Atomic mass of aluminium = 27)?
(c) 10 moles of sodium sulphite (Na2SO3)?

Answer:

(a) The mass of 1 mole of nitrogen atoms is 14g.
(b) The mass of 4 moles of aluminium atoms is (4 × 27)g = 108g
(c) The mass of 10 moles of sodium sulphite (Na2SO3) is 10 × [2 × 23 + 32 + 3 × 16]g
= 10 × 126g = 1260g

Q.No. 8:

Convert into mole.
(a) 12g of oxygen gas
(b) 12g of water
(c) 22g of carbon dioxide

Answer:

(a) 32 g of oxygen gas = 1 mole
Then, 12g of oxygen gas = 12/32 mole = 0.375 mole
(b) 18g of water = 1 mole
Then, 20 g of water = 20/18 mole = 1.11 moles (approx.)
(c) 44g of carbon dioxide = 1 mole
Then, 22g of carbon dioxide = 22/44 mole = 0.5 mole

Q.No. 9:

What is the mass of:

(a) 0.2 mole of oxygen atoms?
(b) 0.5 mole of water molecules?

Answer:

(a) Mass of one mole of oxygen atoms = 16g
Then, mass of 0.2 mole of oxygen atoms = 0.2 × 16g = 3.2g
(b) Mass of one mole of water molecule = 18g
Then, mass of 0.5 mole of water molecules = 0.5 × 18g = 9g
Question 10:
Calculate the number of molecules of sulphur (S8) present in 16g of solid sulphur.
Answer 10:
 1 mole of solid sulphur (S8) = 8 × 32g = 256g
i.e., 256g of solid sulphur contains = 6.022 × 1023 molecules
Then, 16g of solid sulpur contains 6.022×1023
256
× 16 molecules
= 3.76 × 1022 molecules (approx)

Q.No. 11:

Calculate the number of aluminium ions present in 0.051g of aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al
= 27u)

Answer:

1 mole of aluminium oxide (Al2O3) = 2 × 27 + 3 × 16 = 102g
i.e., 102g of Al2O3 = 6.022 × 10⁻²³ molecules of Al2O3
Then, 0.051 g of Al2O3 contains =
6.022 × 10⁻²³ 
102
× 0.051 molecules
= 3.011 × 1020
 molecules of Al2O3
The number of aluminium ions (Al3+
) present in one molecules of aluminium oxide is 2.
Therefore, The number of aluminium ions (Al3+
) present in
3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3) = 2 × 3.011 × 1020
= 6.022 × 1020

Write for the Answers of other Chapter.
For any error report to me

Tuesday, July 9, 2019

हमारे आस पास के पदार्थ

कक्षा नवम

NCERT 

पाठ्य पुस्तक के प्रश्नोत्तर

पदार्थ के भौतिक स्वरूप

1. निम्नलिखित में से कौन से पदार्थ है -
उत्तर-
कुर्सी, वायु, बादाम एवं नीबूं का पानी पदार्थ है क्योंकि यह स्थान घेरता है, द्रव्यमान एवं आयतन दोनों ही होता है।

2. गर्मा गरम खाने की गंध कई मीटर से ही आपके पास पहूँच जाती है लेकिन ठंढे खाने की महक लेने के लिए आपको उसके पास जाना पडता है।
उत्तर-
पदार्थ के कणों की गति तापमान के अनुक्रमाणुपाति होता है। पदार्थ का तापमान बढने से उसके कणों की गति बढती है जबकि घटने से घटती है। अतः गर्मा गरम खाने की गंध कई मीटर से ही हमारे पास पहूँच जाती है जबकी ठंढे खाने की महक लेने के लिए हमे उसके पास जाना पडता है।

3. स्वीमिंग पूल में गोताखोर पानी काट पाता है। इससे पदार्थ का कौन सा गुण प्रेक्षित होता है ?
उत्तर-
पदार्थ के कणों के बीच रिक्त स्थान होता है। पदार्थ का यही गुण प्रेक्षित होता है।

4. पदार्थ के कणों का क्या विशेषताएँ होती है ?

उत्तर-
पदार्थ के कणों की निम्नलिखित विशेषताएँ होती है जो नीचे लिखा गया है।
  1. पदार्थ के कणों के बीच रिक्त स्थान होता है।
  2. पदार्थ के कण निरंतर गतिशील होते है।
  3. पदार्थ के कण एक दुसरे को आकर्षित करते है।

पदार्थ की अवस्थाएँ

1. किसी तत्व के द्रव्यमान प्रति इकाई आयतन को घनत्व कहते है।
घनत्व = द्रव्यमान / आयतन
बढते हुए घनत्व के क्रम में निम्नलिखित को व्यवस्थित करें

उत्तर-
वायु, चिमनी का धुआं, जल, शहद, रुई, चाॅक एवं लोहा।

2. (a) पदार्थ के विभिन्न अवस्थाओॆ के गुणों में  होने वाले अंतर को सारणीबद्ध कीजिए।

उत्तर-
पदार्थ के गुणों में होने वाले अंतर को नीचे सारणीबद्ध किया गया है।

ठोस के आकार एवं आयतन निश्चित होता है।
द्रव्य के आकार अनिश्चित एवं आयतन निश्चित होता है।
गैस के आकार एवं आयतन दोनों ही अनिश्चित होता है।

ठोस अवस्था में पदार्थ के कण एक दुसरें के काफी निकट होते हैं।
द्रव्य अवस्था में पदार्थ के कण ठोस के अपेक्षा दूर लेकिन गैस के अपेक्षा निकट होते है।
गैसीय अवस्था में पदार्थ के कण ठोस एवं द्रव्य के अपेक्षा काफी दूरी पर होते है।

ठोस में कणों की संपीड्यता सबसे  कम होता है अतः ये दृढ होते है।
द्रव्य में कणों की संपीड्यता ठोस के अपेक्षा अधिक एवं गैस के अपेक्षा कम होता है अतः ये तरल होते है।
गैस में कणों की संपीड्यता सबसे अधिक होता है।

ठोस के कणों की गतिज ऊर्जा सबसे कम होता है।
द्रव्य के कणों की गतिज ऊर्जा ठोस के अपेक्षा अधिक लेकिन गैस के अपेक्षा कम होता है।
गैस के कणों की गतिज ऊर्जा सबसे अधिक होता है।

(b) निम्नलिखित पर टिप्पणी कीजिए

उत्तर-
दृढता
वैसे पदार्थ जिसका आकार एवं आयतन निश्चित होता है, जिसमें कण एक दुसरे बहुत नजदीक होते है। इसमें वाह्य बल लगाने पर टूट सकते है लेकिन अपना आकार नही बदलता हो दृढ होते है। पदार्थ के इस गुण को दृढता कहा जाता है। ठोस में ऐसा गुण पाया जाता है।

संपीड्यता

पदार्थ का वह गुण जिसके कारण पदार्थ के अत्यधिक आयतन को एक कम आयतन वाले वर्तन में संपीडित किया जा सकता है, पदार्थ के इस गुण को ही संपीड्यता कहा जाता है।

तरलता

पदार्थ का वह गुण जिसके कारण वह अपना आकार असानी से बदलता है तरलता कहलाता है। द्रव्य में तरलता का गुण पाया जाता है।

बर्तन में गैस का भरना
गैस के कणों की गति अनियमित एवं अत्यधिक तिव्र होती है। इस अनियमित गति के कारण इसके कण बर्तन के दीवारों से से टकराते है जिसके कारण गैस का दबाव बनता है।

गतिज ऊर्जा
ठोस में कणों की गतिज ऊर्जा सबसे कम, द्रव्य में ठोस से ज्यदा एवं गैस से कम जबकि गैस में सबसे अधिक होता है।

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